-- 作者:nima337
-- 发布时间:2012/12/12 10:15:28
-- 回复:(jinzhe)能给出公式吗,我们工作人员进行本地...
didian:=llv(l,2); gaodian:=hhv(h,2); Kcj3:=ref(hhv(h,enterbars+1),1); if h>=gaodian and holding=0 then buy(1,1,thisclose); If holding>0 and ref(h>=gaodian,enterbars)=1 and ENTERBARS>=2 then zy:kcj3-5; if holding>0 and ref(h>=gaodian,enterbars)=1 and enterbars>=2 and l-zy<-0.1 then sell(1,0,thisclose); kKcj3:=ref(llv(l,enterbars+1),1); if l<=didian and holding=0 then buyshort(1,1,thisclose); If holding<0 and ref(l<=didian,enterbars)=1 and ENTERBARS>=2 then kzy:kkcj3+5; if holding<0 and ref(l<=didian,enterbars)=1 and enterbars>=2 and h-kzy>0.1 then sellshort(1,0,thisclose);
这样一堆代码就能检测出问题,15分内会不定重复下单的,固定1秒间隔。
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